Question

pls answer as fast as u could i will give lost of point 4 u

answer before 6:00 today....​

Answer 1

$\longrightarrow \sf \tan(A - B) = \frac{ \tan A - \tan B}{1 + \tan A. \tan B} \\ \\\longrightarrow \sf \tan(60 - 30) = \frac{ \tan 60- \tan 30}{1 + \tan 60. \tan 30} \\ \\ \longrightarrow \sf \tan30 = \frac{ \sqrt{3} - \dfrac{1}{ \sqrt{3} } }{1 + \sqrt{3} \times \dfrac{1}{ \sqrt{3} }} \\ \\ \longrightarrow \sf \tan30 = \dfrac{ \dfrac{3-1}{ \sqrt{3} } }{1 + 1} \\ \\ \longrightarrow \sf \tan30 = \frac{2}{2 \sqrt{3}} \\ \\ \longrightarrow \sf \tan30 = \frac{1}{ \sqrt{3} } \\ \\\longrightarrow \sf \tan30 = \tan30$

LHS = RHS

Hence Proved