Question

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Answer 1

Answer:

Given,

tanθ+secθ=l

tanθ=l−secθ

squaring on both sides, we get,

tan

2

θ=(l−secθ)

2

sec

2

θ−1=l

2

+sec

2

θ−2lsecθ

l

2

−2lsecθ=−1

l

2

+1=2lsecθ

⇒secθ=

2l

l

2

+1