Math, asked by shreya6780, 10 months ago

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The product of three consecutive natural numbers is divisible by

How do I find the 2 numbers when their LCM and HCF are given?. If the HCF and LCM of two numbers 'a' and 'b' are 7 and 56 respectively, then the possible value(/s) of 'a' and 'b' may be

The number in the form of 6p + 5, where p is a whole number, will always be

Answers

Answered by supriths4804

Answer:

1) The product of 3 consecutive natural numbers is always divisible by 3.

2) HCF×LCM=a×b

7×56=a×b

392=a×b

The possible values of a and b are 28 and 14.

3) The number in the form of 6p + 5, where p is a whole number, will always be a whole number.

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