Question

Pls answer basic electronics

Answer 1

Correct option is A

Consider the circuit in the figure. Let the reference potential at A be 0V.

Thus n - terminal of diode in 1V branch is at +1V and p - terminal of diode in 3V branch is at −3V

Thus, the diode in 1V branch is in reverse bias for Vi<1V and forward bias for Vi>1V.

Similarly, the diode in 3V branch is in reverse bias for Vi>−3V and forward bias for Vi<−3V.

As the diodes are ideal, we can replace reverse bias by an open switch and forward bias by a closed switch.

Thus, for Vi<−3V, we have the potential at B as −3V (3V diode in forward bias)

for −3V<Vi<1V, we have Vo=Vi (Both the diodes in reverse bias)

for Vi>1V, we have the potential at B as 1V (1V diode in forward bias)

Hope it helps you