Question

Pls answer best be brainliest fake get reported
In Fig. the side QR of ∆ PQR is produced to a point S. If the bisectors of ∠ PQR and ∠ PRS
meet at point T, then prove that ∠ QTR = ∠ QPR.​

Answer 1

Answer:

< PRS is the external angle

<PRS = < QPR + < PQR.

Step-by-step explanation:

In the given figure, the side QR of PQR is produced to a point S. If the bisectors of <PQR and <PRS meet at point T, then prove that < QRT= 1/2 < QPR

Given

TQ is the bisector of < PQR.

So, <PQT = <TQR = 1/2<PQR

Also,

TR is the bisector of <PRS

So, < PRT = < TRS = 1\2 < PRS

In PQR,

< PRS is the external angle

<PRS = < QPR + < PQR. (External angle is sum of two interior opposite angles)

Answer 2

Step-by-step explanation:

I think there is some mistake in the question