Question

Pls answer by step by step..​

Answer 1

hey mate here is your answer

hope it helps

Answer 2

Formula used :--

• SecA = cosec(90-A)
• cotA = tan(90-A)
• cotA = 1/TanA
• sec45° = √2

Solution :-

sec43° can be written as ,

→ sec43° = sec(90-47°) = cosec47°

Similarly,

cot14° can be written as ,

→ cot14° = cot(90°-76°) = tan76°

And,

→ cot76° = 1/tan76°

→ sec²45 = (√2)² = 2

Putting all these values in Question now we get,

→ (3cosec47°/2cosec47°) + [√2*Tan76° * 1/Tan76° ] + 1 + 2

→ 3/2 + √2 + 3

→ (3/2 + 3) + √2

→ (9/2) + √2

→ (9 + 2√2) / 2 (Ans).