Question

pls answer class 8 ch 3

Answer 1

Answer:

1. 135

2. 110

3. 100

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Answer 2

Step-by-step explanation:

I. let adjacent angle of 110° be y , 45°be z and 70° be a ,x be b

so, 110°+y= 180°

y= 70°

similarly, 45°+z= 180°

z= 135°

and , 70°+a =180°

a=110°

so, by angle sum property of quadrilateral

y+z+a+b =360°

70°+135°+110°+b=360°

315°+b= 360°

b=45°

now , b+ x=180°

45°+x=180°

x=135°

ii. let adjacent angle of 120° be a , 130° be b and x be c

so,

120°+a = 180°

a= 60°

similarly, 130°+b=180°

b= 50°

by angle sum property or triangle

a+b+c =180°

60°+50°+c=180°

110°+c=180°

c=70°

now ,

c+x=180°

70°+x=180°

x=110°

iii. let adjacent angle of 30° be a, 50°be b ,110° be c and 70° be d and adjacent angle of x be g

so ,

30°+a =180°

a=150°

50°+b= 180°

b=130°

110°+c=180°

c=70°

70°+d=180°

d=110°

by angle sum property of quadrilateral

a+b+c+d+g= 360°

150°+130°+70°+110°+z =540°

460°+z = 540°

z=80°

so, 80°+x = 180°

x=100°