Question

pls answer correct and fast​

Answer 1

Answer:

Step-by-step explanation:

Let (11pq + 4q) be a

Let (11pq - 4q) be b

a² - b² = (a+b)(a-b)

(11pq + 4q +11pq - 4q)(11pq + 4q - 11pq + 4q)

(22pq)(8q) = 176pq²

= RHS

Hence Verified.

Answer 2

Question:

• Verify that (11pq + 4q)² - (11pq - 4q)² = 176pq²

Solution:

We have given equation :

(11pq + 4q)² - (11pq - 4q)² = 176pq²

We can use identify i.e (a²-b²) = (a + b)(a - b).

Here,

• a = (11pq + 4q)
• b = (11pq - 4q)

Using the identity:

(11pq + 4q)² - (11pq - 4q)² = 176pq²

→ [(11pq + 4q) + (11pq - 4q)] [((11pq + 4q) - (11pq - 4q)] = 176pq²

→ (11pq + 4q + 11pq - 4q)(11pq + 4q - 11pq + 4q) = 176pq²

→ $\small{\sf{(11pq + 4q {\cancel{+ 11pq}} {\cancel{- 4q}})(11pq + 4q {\cancel{- 11pq}}{\cancel{ + 4q}}}})$= 176pq²

→ (11pq + 4q)(11pq + 4q) = 176pq²

→ (11pq + 11pq)(4q + 4q) = 176pq²

→ (22pq)(8q) = 176 pq²

→ 176pq² = 176pq²

LHS = RHS [Verified]