Pls answer correct
If you will answer correct and step by step I will mark you as brainliest
Attachments:
Answers
Answered by
0
Answer:
ab+bc+ca=0
bc=-ca-ab
bc=-a(b + c)
like wise.
ab=-c(a + b)
ca=-b(c + a)
=1/a square-bc+1/b square-ca+1/c square-ab
=Taking value
1/a square+a(b + c)+1/b square +b(a + c)+1/c square +c(a+b)
1/(a + b + c)+1/ b (a + b + c) + 1/c(a + b + c)
as a b +bc+ca=0
Similar questions