Question

pls answer correctly​

Answer 1

Answer:

According to your question, here the value of secQ is given as 13/12

and we have to find other 5 T-ratios

Let AngleC = theta(Q)

So, According to Angle C =

$ac = hypotenuse \\ \\ bc = base \\ \\ ab = prependicular$

$\sec(c) = \frac{hypotenuse}{base} = \frac{ac}{bc} = \frac{13}{12}$

Hypotenuse² = base² + prependicular²

13² = 12² + x²

169 = 144 + x²

x² = 169 - 144

x² = 25

x = 5

Prependicular = 5cm

Hypotenuse = 13cm

Base = 12cm

$\sin(c) = \frac{prependicular}{hypotenuse} = \frac{5}{13} \\ \\ = \geqslant \cos(c) = \frac{base}{hypotenuse} = \frac{12}{13} \\ \\ = \geqslant \tan(c) = \frac{prependicular}{base} = \frac{5}{12} \\ \\ = \geqslant \csc(c) = \frac{1}{ \sin(c) } = \frac{1}{ \frac{5}{13} } = \frac{13}{5} \\ \\ = \geqslant \sec(c) = \frac{1}{ \cos(c) } = \frac{1}{ \frac{12}{13} } = \frac{13}{12} \\ \\ = \geqslant \cot(c) = \frac{1}{ \tan(c) } = \frac{1}{ \frac{5}{12} } = \frac{12}{5}$