Question

pls answer correctly​

Answer 1

Answer:

cos 45 = 1/√2 sec 30 = 2/√3 cos 30 = √3/2

now , cos 45/sec 30 + cos 30

=> 1/√2 ÷ (2/√3 + √3/2)

=> 1/√2 ÷ (√3 + 2)/2√3

=> (2√3)/√2(√3+2)

=> (√2*√2*√3)/√2(√3+2)

=> √6/√3+2

=> √6(2-√3)/(2+√3)(2-√3)

=> √6 (2-√3)/4-3

=> 2√6 - √18

=> 2√6 - 3√2

Answer 2

hope this may help.....