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Option a
Since, the blocks are in contact, therefore, the acceleration of three of the blocks are same. So, net force acting on A/mass of A=net forcing acting on B/mass of B=net force acting on C/mass of C
=>(60-30)/mA=(30-10)/mB=10/mC
=>mA/3=mB/2=mC
Therefore, mA=3mC, mB=2mC
Therefore, mA:mB:mC=3:2:1
Since, the blocks are in contact, therefore, the acceleration of three of the blocks are same. So, net force acting on A/mass of A=net forcing acting on B/mass of B=net force acting on C/mass of C
=>(60-30)/mA=(30-10)/mB=10/mC
=>mA/3=mB/2=mC
Therefore, mA=3mC, mB=2mC
Therefore, mA:mB:mC=3:2:1
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