Question

Pls answer correctly and fast ​

Answer 1

Answer:

, your answer is given in the above photo

Answer 2

Answer:

$Correct Answer :-$ 14 .

Step-by-step explanation:

$Question :-$

If a = $2-\sqrt{3}$ ,then find  $a^{2} +\frac{1}{a^{2} }$ = ?

$Answer :-$

$a=2-\sqrt{3}\\\frac{1}{a}=\frac{1}{2-\sqrt{3} } \\or \frac{1}{a}=\frac{(2+\sqrt{3}) }{(2-\sqrt{3})(2+\sqrt{3}) } \\or \frac{1}{a}=\frac{(2+\sqrt{3}) }{(2)^{2}-(\sqrt{3})^{2} } \\or \frac{1}{a}=\frac{(2+\sqrt{3}) }{4-3} \\or \frac{1}{a}=(2+\sqrt{3})$

$Let , a^{2} +\frac{1}{a^{2} }=?\\a^{2} +\frac{1}{a^{2} }\\=(2-\sqrt{3})^{2}+(2+\sqrt{3})^{2}\\=(4-4\sqrt{3}+3+4+4\sqrt{3}+3)\\=(4+3+4+3)\\=14$