Question

pls answer correctly and fast
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Answer 1

(1)Possible outcomes when two dice are rolled:

S={(1,1),(1,2),(1,3),....(2,1),(2,2),(2,3),...(6,5)(6,6)}

∴ the number of possible outcomes in the sample space is 36.

The outcomes for the event that the total is odd:

E={(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)}

The number of favourable outcomes is 18.

∴P(E)=

36

18

=

1/2

(2)While throwing two dice, getting a total of 7 consists of these outcomes viz. (1,6),(2,5),(3,4),(4,3),(5,2) and (6,1) out of all possible 36 outcomes. Hence, the required probability is 6/36 = 1/6. Originally Answered: 2 unbiased dice are rolled once.