Question

pls answer correctly no unnecessary ans​

Answer 1

Solution:

1) I think, your question is to verify that (x+y)⁻¹ ≠ 1/x +1/y , when x=2/3 and y=3/5.

(x+y)⁻¹ = ($\frac{2}{3}+\frac{3}{5}$)⁻¹ = ($\frac{2*5 + 3*3}{3*5}$)⁻¹ = ($\frac{19}{15}$)⁻¹

⇒ (x.y)⁻¹ = 15/19 --------------1

$\frac{1}{x} + \frac{1}{y}$ = $\frac{3}{2} + \frac{5}{3}$ = $\frac{3*3+5*2}{2*3}$

⇒ $\frac{1}{x} + \frac{1}{y}$ = $\frac{19}{6}$ --------------2

From 1 and 2 it is clear that (x+y)⁻¹ ≠ 1/x +1/y.

2) Reciprocal of -5/9 is -9/5.

⇒ $\frac{5}{12} * \frac{-9}{5}$ = -3/4

Please mark it as Brainliest.

Answer 2

Answer:

sister which class are you studying

Step-by-step explanation:

i think you poor in math