Question

pls answer dis question...11th

Answer 1

1 mole of Al203 = 102 g

102 g=6.022 × 10^22 atoms

So, 6.022 × 10^22/102 × 0.051

=3.011 × 10^20 atoms

Now, there are 2 aluminium ions in the compound.

So, 2× 3.011 × 10^20

=6.022 × 10^20 aluminium ions