pls answer fasr , i will mark brainiest fr crrect option . i need explination also . pls no spam
Attachments:
Answers
Answered by
37
In the figure below ray AZ bisects DAB and DCB.
(I) State the three pairs of equal parts in ∆BAC and ∆DAC.
(II) Is ∆BAC and ∆DAC? Give reasons.
(III) Is AB = AD? Justify.
(IV) Is CD = CB? Justify.
(II) By ASA (Angle Side Angle) congruence rule ∆BAC ∆DAC.
(III) By CPCT (Corresponding parts of congruent Triangles) AB = AD. (∆BAC ∆DAC).
(IV) Same as third part, By CPCT (Corresponding parts of congruent Triangles) CD = CB. (∆BAC ∆DAC).
Attachments:
Answered by
57
Given
- In figure ray AZ bisects ∠DAB and ∠DAC
To find
- (I) State the three pairs of equal parts in ∆BAC and ∆DAC.
- (II) Is ∆BAC and ∆DAC? Give reasons.
- (III) Is AB = AD? Justify.
- (IV) Is CD = CB? Justify
Solution
- (I) ∠DAC = ∠BAC
- ∠DCA = ∠BCA
- AC = AC
- ΔBAC ≅ ΔDAC
- (II) By ASA (Angle side angle) congruency rule
- (III) As triangles are congruent, AB = AD
- (Corresponding parts of congruent triangles)
- (IV) As triangles are congruent, CD = CB
- (Corresponding parts of congruent triangles)
Similar questions