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(5/3)^2x*(3/5)^9x=1
hint - X=0
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Answer:
x=0
Step-by-step explanation:
(5/3)^2x*(3/5)^9x = 1
(3/5)^-2x*(3/5)^9x = (3/5)^0 [ inverting 5/3 so the power becomes negative][ anything power 0 is 1]
(3/5)^9x-2x = (3/5)^0 [bases are same, powers are added, 9x + (-2x) = 9x - 2x ]
(3/5)^7x = (3/5)^0
taking powers....[a^x = a^y, then x = y]
7x=0
x=0/7
x=0
or of you invert (3/5)^9x, then you'll receive (5/3)^-7x, then solving you'll have -7x=0, X= 0/-7, X=0, or you can write it -x = 0 but I prefer to go with the above method...
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