PLS ANSWER FAST......
A gas in a glass bulb of volume 600 cm3 has a pressure 4 bar. If 50 % of the gas is transferred to another bulb of volume 480 cm3 at the same temperature. Find the gas pressure in the first bulb.
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Answer:
P
i
=1atm
T
i
=20
o
C=293K
V
i
=0.6L
∴
T
i
PiVi
=
293
0.6
let final press be P
T
A
=373K
T
B
=273K
∴
T
A
PV
A
+
T
B
PV
B
=
T
i
P
i
V
i
⇒P(
373
0.4
+
273
0.2
)=
293
0.6
⇒P(
373
2
+
273
1
)=
293
3
⇒P=
293×919
3×373×273
≈1.134atm
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