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a man walks 6km at 12km/h and returns at 10km/h find His average speed
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hola!
This question can be solved in two ways:
1. ] First way:-
→ From A to B:
Distance = 6km
Speed = 12km/h
Time taken = 6 /12 = 0.5 hr
→ From B to A:
Distance = 6km
Speed = 10km/h
Time = distance/ speed = 6/10 = 0.6 hr
Thus,
Average speed = Total distance / Total time taken
= (6 +6) /( 0.5 + 0.6)
= 12 /1.1
= 10.90km/h
2 ] Alternative way:
Average speed = 2v¹v²/ (v¹ + v²)
= (2 × 12 × 10) / (12 + 10)
= 10.90 km/h
Hence,
Average speed of man is 10.90 km/h
hope it helps! :)
This question can be solved in two ways:
1. ] First way:-
→ From A to B:
Distance = 6km
Speed = 12km/h
Time taken = 6 /12 = 0.5 hr
→ From B to A:
Distance = 6km
Speed = 10km/h
Time = distance/ speed = 6/10 = 0.6 hr
Thus,
Average speed = Total distance / Total time taken
= (6 +6) /( 0.5 + 0.6)
= 12 /1.1
= 10.90km/h
2 ] Alternative way:
Average speed = 2v¹v²/ (v¹ + v²)
= (2 × 12 × 10) / (12 + 10)
= 10.90 km/h
Hence,
Average speed of man is 10.90 km/h
hope it helps! :)
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