Question

pls answer fast .....
answer is 33.5​

Answer 1

Answer:

As , ABCD is a rhombus

Therefore , angle BCD= angle DAB

= 73° ( opposite angles of rhombus are equal)

in ∆ ABD

As, AB = DA ( all sides of rhombus are equal)

angle ADB= angle ABD ( angles opposite To equal sides are equal) - - - - ( I )

angle ABD+ angle BDA+ angle DAB = 180° { angle sum property of a triangle)

angle BDA + angle BDA + angle DAB = 180° { By ( I )

2angle BDA +73 ° = 180°

angle BDA = 180° -73° / 2

angle BDA = 53.5°

For triangle ADE

angle BDA = angle AED + angle EAD ( exterior angle property of a triangle )

angle EAD = angle BDA - angle AED

Y = 53.5° - 20°

Y = 33.5 °

I hope it has helped you