Question

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Answer 1

Answer:

i. 313.14*10²³ atoms.

ii. 13 atoms.

iii. 7.83* 10²⁴ atoms.

Explanation:

1 mole = 6.022*10²³ atoms

i. 52 moles of Helium = [ 52 * 6.022 ] * 10²³

= 313.14*10²³ atoms

ii. Atomic mass of Helium = 4 amu = 1 atom

If 4 amu is the mass of 1 atom of helium, then,

No. of helium atoms that will have 1 amu = 1/4 atoms

= 0.25 atoms

= No. of helium atoms that have 52 amu = [52*0.25] atoms

= 13 atoms

iii. Atomic mass of Helium = 4g = 1 mole = 6.022*10²³ atoms

No. of atoms in 1g of Helium = [6.022*10²³] / 4 atoms

No. of atoms in 52 g of helium = [(6.022*10²³) /4 * 52] atoms

= 7.83* 10²⁴ atoms

Hope this helps.

Answer 2

Answer:

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