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Answered by
1
Answer:
(i) 24ohm
(ii) 6/24 A = 1/4 A = 0.25A
(iii) electric lamp = 20 x 0.25 = 5 V
conductor = 4 x 0.25 = 1 V
(iv) P = I²R
P = 0.25 x 0.25 x 20
P = 1.25 W
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Answered by
0
Answer:
Explanation:
a) 4 +20 =24 ohm
b)V/R=6/24=1/4=0.25A
c) i)v=IR
=0.25 x 20
=5v
ii)v=IR
=0.25 x 4
=1v
d) P=VI
=5x0.25
=5/4w
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