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change in internal energy is a state function so it will depend on the initial and final states and not on the path taken. therefore internal energy for path iaf will be equal to the internal energy but opposite in sign for path fi
Q=dU+W
dU=80–50=30 Cal
for the curved path
dU= –30 cal, W= –30 cal
Q= –60 cal option d
Q=dU+W
dU=80–50=30 Cal
for the curved path
dU= –30 cal, W= –30 cal
Q= –60 cal option d
mimansha2712:
Thank you
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