Physics, asked by awsmaditri, 6 hours ago

PLS ANSWER FAST I NEED IT IN URGENCY. ILL MARK BRAINLIEST.

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Answers

Answered by itzmecuterose
6

Answer:

23°N

Explanation:

Follow and Mark me as brainliest

Answered by siddharth6395
2

Answer:

Given-

u=20m/s , θ=30

o

, t=0.5s

Initial velocity-

u

=ucosθ

i

^

+usinθ

j

^

u

=u(cos30

o

i

^

+sin30

o

j

^

)

u

=20(

2

3

i

^

+

2

1

j

^

)

u

=10

3

i

^

+10

j

^

acceleration a=−g

j

^

=−10

j

^

since acceleration is acting downward

v

=

u

+

a

t

v

=(10

3

i

^

+10

j

^

)−(10

j

^

×0.5)

v

=10

3

i

^

+5

j

^

Change in velocity=Δ

v

=

v

u

=−5

j

^

Magnitude of change in velocity =5m/s

A short method is-

Δ

v

=acceleration×t=10×0.5=5m/s

Explanation:

bro my method is a bit different and question also but you can take from it I just need one brainliest

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