Question

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Answer 1

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sєє тнє αттα¢нємєηт.....

..ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘᴇᴅ....

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Answer 2

Answer:

sec θ + tan θ = 1/(2x) or 2x

Step-by-step explanation:

sec θ = x + 1/(4x) (given)

sec²θ = x² + 1/(16x²) + 2(x)(1/(4x))    [Squaring both sides]

sec²θ - 1 = x² + 1/(16x²) + 1/2 - 1 [Subtracting 1 from both sides]

tan²θ = x² + 1/(16x²) - 1/2 = (x)² + (1/(4x))² - 2(x)(1/4x) [∵sec²θ = 1 + tan²θ]

tan²θ = (x - 1/(4x))²

tanθ = ±(x - 1/(4x))² = 1/4x - x or x - 1/4x [taking both positive and negative roots]

tanθ + secθ = 1/(4x) - x + x + 1/(4x) or x - 1/(4x) + x + 1/(4x)

tanθ + secθ = 2/(4x) or 2x

tanθ + secθ = 1/(2x) or 2x

HOPE IT HELPS