pls answer fast i will mark most bainley
Answers
Step-by-step explanation:
37 will be the answers
Multiply all terms by the same value to eliminate fraction denominators
6
2
9
=
1
7
\frac{629}{x}=17
x629=17
⋅
6
2
9
=
⋅
1
7
x \cdot \frac{629}{x}=x \cdot 17
x⋅x629=x⋅17
2
Cancel multiplied terms that are in the denominator
⋅
6
2
9
=
⋅
1
7
x \cdot \frac{629}{x}=x \cdot 17
x⋅x629=x⋅17
6
2
9
=
⋅
1
7
629=x \cdot 17
629=x⋅17
3
Re-order terms so that constants are on the left
6
2
9
=
⋅
1
7
629=x \cdot {\color{#c92786}{17}}
629=x⋅17
6
2
9
=
1
7
629={\color{#c92786}{17}}x
629=17x
4
Divide both sides of the equation by the same term
6
2
9
=
1
7
629=17x
629=17x
6
2
9
1
7
=
1
7
1
7
\frac{629}{{\color{#c92786}{17}}}=\frac{17x}{{\color{#c92786}{17}}}
17629=1717x
5
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left
=
3
7
Answer:
Options A and C
Step-by-step explanation:
Please Mark me as the Brainliest