Math, asked by adityachauhand45, 9 hours ago

pls answer fast
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Answered by aryankhaneja7
0

Answer:

25cmsq

Step-by-step explanation:

Answered by Talpadadilip783
3

\mathbb\red{ \tiny A \scriptsize \: N \small \:S \large \: W \Large \:E \huge \: R}

 \rule{300pt}{0.1pt}

Here, the width of the frame

\[ \begin{array}{l}  \rm=\dfrac{24 cm -16 cm }{2} \\  \\  \rm=\dfrac{8}{2} cm  \\  \\  \rm=4 cm \end{array} \]

Area of section ABQP= Area of section CDSR

\[ \begin{array}{l} \rm =\dfrac{1}{2} \times( AB + PQ ) \times 4 cm ^{2} \\  \\  \rm=\dfrac{1}{2} \times(28+20) \times 4 cm ^{2} \\  \\  \rm=48 \times 2 cm ^{2} \\  \\   \color{darkcyan}\boxed{ \rm = 96 \:  {cm}^{2} } \end{array} \]

Area of section BCRQ = Area of section APSD

\[ \begin{array}{l} \displaystyle\rm  =\frac{1}{2} \times( BC + QR ) \times 4 cm ^{2} \\  \\\displaystyle\rm =\frac{1}{2} \times(24+16) \times 4 cm ^{2} \\  \\\displaystyle\rm =40 \times 2 \\  \\ \color{red}\boxed{   \rm=80 cm ^{2}} \quad \text { } \end{array} \]

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