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(Sec A + Cos A) (Sec A - Cos A)
We know that,
(a - b) (a + b) = a² - b²
Here,
a = Sec A
b = Cos A
Substituting,
Sec² A - Cos ² A
We know that,
1 + Tan² A = Sec² A
1 - Sin² A = Cos² A
Substituting,
1 + Tan² A - (1 - Sin² A)
1 + Tan² A - 1 + Sin² A
Tan² A + Sin² A
Therefore,
\boxed{\purple{\textsf{(Sec A + Cos A) (Sec A - Cos A) = Tan² A + Sin² A}}}
(Sec A + Cos A) (Sec A - Cos A) = Tan² A + Sin² A
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