Question

pls answer fast it's urgent

Answer 1

In this question draw line from B to D
and find interior angel of triangle BDC
angel ABC + BDC = 180 because linear angel pair
so 180- 124 = 56
and similar like this
180-122=58
sum of all angel of triangle BDC = 180
SO 56+58 =180
180-114= 66 angel C = 66

Answer 2

Hello Mate!

Draw CF parallel to CE.

Then, < CDE + < DCF = 180° [ Interior consecutive angles ]

122° + < DCF = 180°

< DCF = 58°

Now, < ABC = < BCF = 124° [ Alternate angle ]

< BCF = < BCD + < DCF

124° = < BCD + 58°

124° - 58° = < BCD

66° = < BCD

Hence value of angle BCD is 66°

Have great future ahead!