Question

pls answer fast.Maths question chapter-factorisation





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Answer 1

$\huge\mathbb\blue{Here\:is\:Your\:answer}$

Given,

$2x^2-18$

$\text{taking 2 as common}$

$2(x^2-9)$

$2(x^2-3^2)$

$\text{Using(a^2-b^2)=(a+b) (a-b) }$

$2(x^2+3) (x^2-3)$

$\text\underline\huge{Useful Identities}$

$(a+b)^2=a+b+2ab$

$(a-b)^2=a^2-2ab+b^2$

$(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac$

$(a^3+b^3)=a^3-ab+b^3$.

Thank You!

#Bebrainly