Pls answer fast P(x) x⁴-x³-3x²+3x+2 g(x) ? q(x) x²-x-2 R(x) 2x
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It is given P(x) = x³-6x²+3x+10 and g(x) = x+1
We have to find r(x)-remainder function and q(x)-quotient function
Solving it using long division method
see it in ATTACHMENT...
We get x³-6x²+3x+10 = (x+1)*(x²-7x+10) + 0
Dividend =( Divisor * Quotient )+ Remainder
Now r(x) = 0 and q(x)=(x²-7x+10).
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