Question

pls answer fast
pls answer fast got no time that's why and dont simply spam somthing

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Answer 1

Answer:

punyeta nag grade 8 den akong wlang alam sorry sorry:)

Answer 2

ANSWER:

d) (x^2 - 1)/x

SOLUTION:

Given secθ+tanθ=x⋯(1)

As we know that,

sec^2 θ−tan^2 θ=1

⟹(secθ−tanθ)(secθ+tanθ)=1                   (∵a^ 2 −b^ 2  =(a+b)(a−b))

⟹secθ−tanθ=  x - 1/x  ⋯(2)

Subtracting (2) from (1)

⟹2tanθ = x−   1/x  = (x^2 - 1)/x

​ ⟹tanθ = (x^2 - 1)/x

​Hope it helps!

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