Question

pls answer fast pls its urgent

Answer 1

Step-by-step explanation:

Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D

Now in triangles ABD and ACD We have AB=AC (Given)

∠BAD=∠CAD (because AD is bisector of ∠A

AD=AD (Common side)

Therefore by SAS congruence condition we have

△ABC≅△ACD

⇒∠B=∠C

(Corresponding parts of congruent triangles are equal )

Answer 2

Answer:

angle opposite to equal sides of an isosceles triangle are equal.

given : isosceles triangle ABC

i.e. AB = AC

to prove : angle B = angle C

construction : draw a bisector of angle A intersecting BC at D.

proof :

In ∆ BAD and ∆ CAD

AB = AC [given]

angle BAD = angle CAD [by construction]

AD = AD [common]

∆BAD ~= ∆CAD [by SAS congruence rule]

thus,

angle ABD = angle ACD [by CPCT]

=> angle B = angle C

hence, angle opposite to equal sides are equal.

hence proved.

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