Math, asked by perobero, 10 days ago

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Answered by mitrasamar1973
2

Answer:

Answer: Let x−11=X and y−21=Y

Hence, the given equations are reduced to:

5X+Y=2            ....(1)

6X−3Y=1          ....(2)

Multiplying (1) by 3, we get

15X+3Y=6       ....(3)

Adding (3) and (2), we get

21X=7

⇒X=3/1

Substitute this value of X in (2), we get

6(3/1)−3Y=1

⇒2−3Y=1

⇒3Y=1

⇒Y=3/1

Resubstitute the values of X and Y to get x and y,

X=x−11

⇒3/1=x−11

⇒x−1=3

⇒x=4

Y=y−2/1

⇒3/1

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