Question

pls answer fast. sorry for the diagram

Answer 1

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angle CAO = 60 degree...


OAB + ABO + BOA = 180
OAB + OAB + 90 = 180 = 2OAB = 180- 90
angles opposite to equal sides are equal angle sum property of a triangle.
OAB = 90/2 = 45
In ACB, ACB + CBA + CAB = 180
45+ 30+ CAB = 180
CAB = 180 – 75= 105
CAO+ OAB = 105
CAO + 45= 105
CAO = 105 – 45 = 60

Answer 2

heyy....here is ur ans....✌❤❤

⏩It is given that angle AOB = 90° & angle ABC = 30°

⏩So in triangle OAB..

⏩Since OB and OA are radius of cirlce so OA = OB. Then if the sides are equal angles are also equal so <OBA = <OAB = 45°

⏩Since we know that angle subtended from the centre of the circle is half the angle at any point of the circle.

⏩So angle ACB = 45°

⏩Now in triangle CAB
By angle sum property of a triangle
<CAB + <ABC + <BCA = 180°
<CAB + 30° + 45° = 180°
<CAB = 180 - 75
<CAB = 105°

⏩So now <CAB - <OAB = <CAO
= 105°- 45°= 60°
So angle CAO = 60.

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