Question

Pls answer fast
The question is in the attachment.
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Answer 1

We have, N=420.

Then, 2N=2420=210

The cumulative frequency just greater than 2N is 275 then 

165.5−168.5 is the median class such that, L=165.5,f=142,F=133 and h=168.5−165.5=3

⇒  Median=L+f2N−F×h

Median=165.5+142210−133×h

Median=165.5+1.63

∴  Median= 167.13