Question

pls answer fast tomorrow is board​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

We know that-

Angle P = 60° ( Equilateral triangle)

Angle Q = 60° ( Equilateral triangle)

Angle R = 60° ( Equilateral triangle)

Radius = 4cm

such that,

QD = 4cm ; DP = 4cm ; PF = 4cm ; FR = 4cm ; ER = 4cm ; QE = 4cm

So,

QD+DP = 4cm + 4cm => QP = 8cm

PF + FR = 4cm+ 4cm => PR = 8cm

QE + ER = 4cm + 4cm => QR = 8cm

We know that "Area of sector of Angle" = Q/360° × Πr^2

Therefore, Area Of Sectors of QDE, REF, PFD = 60°/360° × 3.14× (4)^2 × (3) = 25.12cm^2

We know that Area of Equilateral triangle PQR = √3/4(a)^2

√3/4(8cm)^2 = 27.71(Approx)

Area of shaded Region = (Area of equilateral triangle PQR) - (Area of Sectors of QDE, REF, PFD)

=> (27.71 - 25.12)cm^2

=> 2.59cm^2

Therefore, The area of the shaded region in an equilateral triangle is 2.59cm^2

Hope it helps!☺