Question

pls answer fast...urgent and give correct answers​

Answer 1

Step-by-step explanation:

answer 5 one

radius=28cm

perimeter of circle=2πr,2×22/7×28

=176cm=1.76m

and total distance is 704m

therefore number of revolution=704/1.76=400

400 revolution

2one

side=100 and length of footpath is 5

therefore inner square has side 95

therefore area of footpath=area of outer square-area of inner square

100×100-95×95

10000-9025=975m^2

Hope it helps........

Answer 2

Answer:

1.Side of the square=22cm

perimeter of the square=4×22=88

circumference of the circle=perimeter of the square

circumference of the circle=

$2\pi \: r$

=2×22/7×r=88

=44/7×r=88

=r=88×7/44

=r=2×7

=r=14cm

2.area of the park without the path=100^2=10000m^2

area of the park with the path=110^2=12100m^2

Therefore,area of the path=12100-10000=2100m^2.

3.diameter=7m

radius=3.5m

circumference=

$\pi \: d$

=22/7×7

=22m

area=

$\pi \: {r}^{2}$

=22/7×3.5×3.5

=22/7×35/10×35/10

=(22×5×35)/100

=(110×35)/100

=3850/100

=38.5m^2.

4.Perimeter of the wheel=

$2\pi \: r$

=2×22/7×28

=2×22×4

=88×2

=176cm

Now,distance=704×100cm=70400cm

Now,revolutions=70400/176=400

Hope it helps

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