Question

pls answer fast who will aswer first will be marked as a brainlist​

Answer 1

x will be 132-232 sincerely it is the right answer and even the teachers will give you right even if you don't do the calculations

Answer 2

ANSWER: 5

Mistake in question:

I think that it should be $K_{a}$ in place of $K_{b}$

SOLUTION:

Reaction: NaC₃H₅O₃ + HCl ---> C₃H₆O₃ + NaCl

at t = 0...------1----------------x₀-------------0------------0

As HCl is a strong acid, therefore it will react completely.

at t = t eq...--(1-x₀)--------(x₀-x₀)---------x₀-------------x₀

$p^{H}=p^{K_{a} }+log\frac{(salt)}{(acid)}$

$=> 3.77 = 3.89 + log\frac{1-x_{0} }{x_{0} }\\=> \frac{x_{0} }{1-x_{0} }=10^{0.08}\\=> \frac{x_{0} }{1-x_{0} } = 1.2\\=>x_{0}=0.55$

=>0.55×10³ ml = 110× x

=> x = $\frac{550}{110}\\ =5$

I HOPE IT HELPS YOU...!!!

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