Question

pls answer fast with an explanation

Answer 1

(15/7)a^2b×(-7/9)ab=(-15/9)a^3b^2

if we substitute a=2&b=3

in (-15/9)a^3b^2 we get

(-15/9)(2^3)(3^2)

=(-15/9)(8)(9)

=-120

therefore (-15/9)a^3b^2 value for a=2& b=3 is (-120)

Answer 2

Answer:

-5/3a^3b^2

Step-by-step explanation:

First let's separate the numerical and variable terms.

So it will become 15/7 × -7/9 a^2b × ab

Then the common factor of 15 and 9 is 3 so when you will divide then 15÷3 = 5 and 9÷3 = 3

Then the common factor of 7 and -7 is 7 so when you will divide it will become 7÷7 = 1 and -7÷7 = -1

So it will become -5/3

Then on the variable side it was a^2b × ab = a^3b^2

In these type of conditions add the powers

So a^2+1 × b^1+1 = a^3b^2

So it will become -5/3 × a^3b^2 = -5/3a^3b^2

VERIFICATION :-

a = 2 and b = 3

15/7 a^2b × -7/9 ab

Then put the values at their respective places

15/7 × 2^2 × 3 × -7/9 × 2 × 3

15/7 × 4 × 3 × -7/9 × 6

15/7 × 12 × -7/9 × 6

180/7 × -42/9

Then when you will solve it the common factor of 7 and -42 is 7 so 7÷7 = 1 and -42÷7 = -6

And the common factor of 180 and 9 is 9 so 180 ÷ 9 = 20 and 9÷9 = 1

So it will come : 20 × -6 = -120

THUS VERIFIED