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Answers
Question :-
Two boys starting at the same point, walk in opposite directions for x metres, turn right and walk another y metres, and turn right and walk another x metres. What is the distance between them?
A) 2 y + 2 x
B) 2 y ✔✔
C) 2 x
D) y + x
Answer :-
Explanation :-
♠︎ While dealing with the questions related to Distance, and direction it is convenient to draw figures according to the given information.
Refer to the figure attached
✤ O is the starting point from where two boys started walking.
✤ From O Boys walked a distance x metres such that OA = OP = x metres.
✤ Then they turned right according to their respective positions and walked a distance y metres such that AB = PQ = y metres.
✤ Again they turned right accord to their respective positions and walked a distance of x metres, i.e, BC = QR = x metres.
✤ Currently they are standing at C and R and we have to find distance CR .
✤ As we can conclude in the figure that
AB + PQ = CO + RO = y + y = 2 y metres.
● Hence, the distance between the two boys is 2 y metres.
Answer:
Answer:
Power (P) =2kw =2000w
Power(P) in watts =J/s
1 watts = 1 J/s
Therefore , 2000w = 2000 J/s
One minute = 60 seconds
Power (P) is also given by
P= Work done ( W )/( t ).....( 1 )
w = mgh
Height (h) = 10m
g = 9.8m/s2
Applying all the above data in equation( 1 )
P=(m×9.8×10) / 60
Therefore, m = 1224.489 Kg
Thus , the electric pump can lift 1224.489 Kg , every minute to height of 10 m.
I wish it was helpful for you.