Question

pls answer fast with steps

Answer 1

Hey☺.. Here is your answer u r looking for..

In ∆ABD and ∆BCD we have

BD = BD (common)
AB = BC (Given)
AD = CD(Given)

Hence,∆ABD Congruent ∆BCD(S.S.S congruence)....PROVED

So,<CDB = <ADB

y -7 =38
y = 38+7
y = 45

and

<CBD = <ABD
x + 5= 50
x =50 - 5
x = 45

Answer 2

In triangle ADB & CDB

I) Seg AD = Seg CD.; ... (given)

II) Seg BC=Seg AB. .... (given)

III)Seg BD= Seg BD. ...(common side)

so Triangle ADB=CDB