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Let AB is parallel to FG, then ZABE=ZBEG=120°(Alternate angles)
Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FG
Therefore, considering CD || FG and CE is
the transversal, then ZDCE+ZCEG=180°(Co-interior angles)
100°+/CEG=180°
ZCEG-80°
Now, <BEG=<BEC+<CEG
120°=x+80°
x=40°
Thus, the value of the <BEC=x=40°
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