Math, asked by magicbeginshere, 8 months ago

#PLS ANSWER FAST
(X^a)^b)^1/ab (x^b)^c)^1/bc (x^c)^a)^1/ca

note that the answer
is not 1 and
the question is not
(xa/xb)1/ab (xb/xc)1/bc (xc/xa)1/ca = 1

Answers

Answered by Anonymous
1

Answer:

L.H.S. = (xa/xb)1/ab (xb/xc)1/bc (xc/xa)1/ca

= (x a-b)1/b (xb-c)1/bc (xc-a)1/ca

= x a-b/ab xb-c/bc x c-a/ca

{(xa)b = xab}

= x a-b/ab + b-c/bc +c-a/ca

= x (ac – bc + ab – ac + bc – ab)/abc

= x0 = 1 = R.H.S  (∵XO = 1)

Step-by-step explanation:

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