pls answer fasttttttttttt
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Bhai agar pata hota to 8th
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Joining Q to S will break this quadrilateral into two triangles. Each triangle has the sum of its angles as 180°. So, two triangles will have the sum of their angles as 2 × 180° = 360°.
In ∆PQS :-
<P + <PQS + <PSQ = 180° ---(1)
{angle sum property of a triangle}
In ∆QRS :-
<R + <RQS + <RSQ = 180° ---(2)
{angle sum property of a triangle}
Adding (1) & (2) :-
<P + <R + (<PQS + <RQS) + (<PSQ + <RSQ) = 360°
<P + <R + <Q + <S = 360°
or, <P + <Q + <R + <S = 360°
- Q.E.D.
Hope, it'll help you.....
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