pls answer
FOR: BRAINLIEST
Answers
Answer:no it doesnt have
Step-by-step explanation:
Answer:
determine whether the given quadratic equation has real roots and if so, find the roots 6x²+x=0
Step-by-step explanation:
Answer:
\begin{gathered}answer \\ x = \frac{1}{2} \\ \\ x = \frac{ - 2}{3}\end{gathered}
answer
x=
2
1
x=
3
−2
Step-by-step explanation:
\begin{gathered}\large \bold \red{ \underline{ \underline{to \: \: find}}} \\ quadratic \: \: equation \: \: has \: \: real \: \: roots \: \: and \: \: if \: \: so \\ find \: \: the \: \: roots \: \: of \: \: equations \: \: 6 {x}^{2} + x - 2 = 0 \\ \large \bold \orange{ \underline{ \underline{explanation}}} \\ \large \bold \green{notes} \\ 1) = \: if \: \: d > 0 \: \: roots \: \: are \: \: real \: \: and \: \: unequal \\ 2) = if \: \: d = 0 \: \: roots \: \: are \: \: real \: \: and \: \: equal \\ 3) =if \: \: d < 0 \: \: roots \: \: are \: \: imaginary \\ \\ \large \bold \pink{check \: \: the \: \: nature \: \: of \: \: roots} \\ 6 {x}^{2} + x - 2 = 0 \\ d = {b}^{2} - 4ac \\ d = {1}^{2} - 4(6)( - 2) \\ d = 1 + 48 \\ d = 49 \\ it \: \: means \: \: roots \: \: are \: \: real \: \: and \: \: equal \\ x = \frac{ - b + \sqrt{d} }{2a} \\ x = \frac{ - 1 + \sqrt{49} }{12} \\ \\ x = \frac{ - 1 + 7}{12} \\ \\ x = \frac{6}{12} \\ \\ x = \frac{1}{2} \\ \\ x = \frac{ - b - \sqrt{d} }{2a} \\ \\ x = \frac{ - 1 - \sqrt{49} }{12} \\ \\ x = \frac{ - 1 - 7}{12} \\ \\ x = \frac{ - 8}{12} \\ \\ x = \frac{ - 2}{3}\end{gathered}
tofind
quadraticequationhasrealrootsandifso
findtherootsofequations6x
2
+x−2=0
explanation
notes
1)=ifd>0rootsarerealandunequal
2)=ifd=0rootsarerealandequal
3)=ifd<0rootsareimaginary
checkthenatureofroots
6x
2
+x−2=0
d=b
2
−4ac
d=1
2
−4(6)(−2)
d=1+48
d=49
itmeansrootsarerealandequal
x=
2a
−b+
d
x=
12
−1+
49
x=
12
−1+7
x=
12
6
x=
2
1
x=
2a
−b−
d
x=
12
−1−
49
x=
12
−1−7
x=
12
−8
x=
3
−2