Question

Pls answer for first and second question I will mark u as brainliest plssss urgent with steps and formula

Answer 1

Answer:

1) 10 n 2) i) 29.4 ii) 2*10^3

Explanation:

we know that

buoyant force = density* g*v

                        = 10 * 10^3/ 10^3

                        = 10 N

                      (or)

v = mass / density

v = 4/4000

v= 0.001

and buoyant force=  density* g*v

                              =  10 * 10^3 * 0.001

                               =  10^3 * 10^-2

                                =  10 N    

for 2 nd question

we know that

mass = volume * density

therefore

density = mass / volume

            =  6 / 3 * 10^-3

             =  2* 10^3

and

buoyant force=  density* g*v

                      =  10^3 * 9.8*3*10^-3

                      =  9.8 * 3

                      =  29.4    

thank u

hope this will help you!!!!!

Answer 2

Answer:

• Buoyant Force (F) = 10 N.
• Buoyant Force (F) = 29.40 N & Density of Water (ρ) = 2 x 10³ Kg/m³.

Given:

• First Question:-

1. Mass of the Ball (M) = 4 Kg.
2. Density of Ball (ρ) = 4000 Kg/m³.
3. Acceleration due to gravity (g) = 10 m/sec².

• Second Question:-

1. Volume of Block (V) = 3 x 10⁻³ m³.
2. Density of water (σ) = 10³ kg/m³.

Explanation:

$\rule{300}{1.5}$

First Question :-

Firstly we need to find the Volume of Ball.

From relation we know,

Density = Mass/volume

⇒ ρ = M/V

Substituting the values,

⇒ 4000 Kg/m³ = 4 Kg/V m³

⇒ 4000 = 4/V

⇒ V = 4/4000

⇒ V = 1/1000

⇒ V = 1 x 10⁻³ m³

⇒ V = 10⁻³ m³.

From Buoyant Force Formula,

F = V x σ x g

⇒ F = Vσg

∵[σ = Density of Water]

Substituting the values,

⇒ F = 10⁻³ x 10³ x 10

∵ [g = 10 m/sec²]

⇒ F = 1 x 10

⇒ F = 10 N.

The, Buoyant Force Acting on the ball is 10 Newton.

$\rule{300}{1.5}$

$\rule{300}{1.5}$

Second Question :-

i) Buoyant Force

From Buoyant Force Formula,

F = V x σ x g

⇒ F = Vσg

∵ [ σ = Density of water]

Substituting the values,

⇒ F = 3 x 10⁻³ x 10³ x 9.8

∵ [g = 9.8 m/sec²]

Simplifying,

⇒ F = 3 x 9.8

⇒ F = 29.4 N.

So, The Buoyant Force is 29.4 Newtons.

ii) Density

From Relation.

Density = Mass/volume

⇒ ρ = M/V

Substituting the values,

⇒ ρ = 6 kg/3 x 10⁻³ m³

⇒ ρ = 6/3 x 10⁻³

⇒ ρ = 6 x 10³/3

⇒ ρ = 2 x 10³ Kg/m³.

So, The Density of the Material is 2 x 10³ Kg/m³.

$\rule{300}{1.5}$