pls answer for this question
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Answered by
1
Solution :-
(x+y+z )³=( 0)³
x³+y³+z³-3xyz=0
x³+y³+z³= 3xyz AnsWer
(x+y+z )³=( 0)³
x³+y³+z³-3xyz=0
x³+y³+z³= 3xyz AnsWer
Answered by
7
x^3+y^3+z^3-3xyz= (x+y +z)( x^2+y^2+z^2-xy- yz - zx)
now x+y+z= 0
x^3+ y^3+z^3= 3xyz
hopes so it will help you
now x+y+z= 0
x^3+ y^3+z^3= 3xyz
hopes so it will help you
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