Question

pls answer for this question ​

Answer 1

Answer:

Explanation:

For calculating equilibrium constant,we need to apply law of mass action.

Kc=[AB]^2/{[A2]*[B2]}∆n(Change in number of gaseous moles)=

2-(1+1)=0Now,Kp=Kc{(RT)^∆n}

In x,we see that reactant molecules are in excess and more crowded as compared to y.

So, for x, reaction will proceed in forward direction,but for y, reaction will be in backward direction.

Since, change in gaseous moles is nil,so increase in pressure doesn't affect the equilibrium mixture

Answer 2

Answer:

yes it will number three